Question

K Question 3 of 5 > 10 The IR (infrared) spectra of two pure compounds (0.020 M compound A in solvent and 0.020 M compound B
0 0
Add a comment Improve this question Transcribed image text
Answer #1

wave number (cm-1)

A

B

unknown

3030

0.456

0.0315

0.4179

2976

0.119

0.377

0.278

Absorbance = A = E x b x C

wave number

A

B

3030

E = 23 M-cm-1

1.6 M-1 cm-1

2976

E = 6.0 M-1 cm-1

19 M-1 cm-1

0.4179 = 23 x 1 x A + 1.6 x 1 x B

0.4179 = 23 A + 1.6 B ----------------------(1)

0.278 = 6 x 1 x A + 19 x 1 x B

0.278 = 6 A + 19 B ---------------------(2)

by solving these two

A = 0.0175 M

B = 0.00909 M

Add a comment
Know the answer?
Add Answer to:
K Question 3 of 5 > 10 The IR (infrared) spectra of two pure compounds (0.020 M compound A in sol...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 100 The IR (infrared) spectra of two pure compounds 90 (0.020 M compound A in solvent...

    100 The IR (infrared) spectra of two pure compounds 90 (0.020 M compound A in solvent and 0.020 M compound B 80 in solvent) are given. The pathlength of the cell is 1.00 cm. 970 The y-axis in the spectra is transmittance rather than 60 50 absorption, so that the wavenumbers at which there is a dip 40 in the curve correspond to absorption peaks 2976 cm 30 3030 cm Pure A A mixture of A and B in unknown...

  • Please show work! A solution containing a mixture of the compounds X and Y had an absorbance of 1.06 at 443 nm and...

    Please show work! A solution containing a mixture of the compounds X and Y had an absorbance of 1.06 at 443 nm and an absorbance of 0.909 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (C) of X and Y at each wavelength are shown in the table. Wavelength (2. nm) Molar Absorptivity (M 'cm ) 3507 443 520 14860 3616 5818 What are the concentrations of X and Y in this mixture? Transmittance (%)...

  • 3. Individual spectra of pure compounds A and B were taken using 1.00 x 10M solutions...

    3. Individual spectra of pure compounds A and B were taken using 1.00 x 10M solutions of each, using a cell with a 5.00 cm path length. The transmittance data for each solution at two key wavenumbers are as follows: Solution ) % Transmittance at Wavenumber (cm 2022 1993 31.0 79.7 97.4 20.0 Pure A Pure B An unknown mixture of A and B in a 5.00 cm cell gave transmittance values of 50.6% at 2022 cm? and 20.1% at...

  • The figure shows the absorption spectra of two pure compounds, A and B, each at a...

    The figure shows the absorption spectra of two pure compounds, A and B, each at a concentration of 1.50×10−4 M. The table shows the measured absorbance of these standards in a 1.000 cm pathlength cell at five different wavelengths, along with the absorbance of an unknown mixture of the two compounds at the same wavelengths. Wavelength (nm) Compound A standard Compound B standard Mixture 440 0.430 0.213 0.268 470 0.642 0.367 0.434 500 0.609 0.444 0.478 530 0.392 0.457 0.427...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT