The gas mileages (in miles per gallon) of 25 randomly selected sports cars are listed in the accompanying table. Assume the mileages are not normally distributed. Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results.
20 31 17 20 19 24 17 23 25 21 21 30 17 22 23 24 21 24 21 18 19 19
Let sigma be the population standard deviation and let n be the sample size. Which distribution should be used to construct the confidence interval? ____________ can be used to construct the confidence interval, since ___________.
Identify the confidence interval. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. (__,__) (Round to one decimal place as needed.)
B. Neither the standard normal distribution nor the t-distribution can be used to construct the interval.
The gas mileages (in miles per gallon) of 25 randomly selected sports cars are listed in...
The gas mileages (in miles per gallon) of 28 randomly selected sports cars are listed in the accompanying table. Assume the mileages are not normally distributed. Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. 囲Click the icon to view the sports car gas mileages. Let o be the population standard deviation and let n be the...
The data below represents the overall miles per gallon (MPG) of 2008 SUVs priced under $30,000. Complete parts a and b below. 24, 18, 22, 20, 18, 19, 16, 16, 20, 18, 20, 18, 21, 18, 18, 19, 16, 17, 16, 21,17, 21 a. Construct a 95% confidence interval estimate for the population mean miles per gallon of 2008 SUVs priced under $30,000, assuming a normal distribution. s μ s DRound to two decimal places as needed.) b. Interpret the...
The table below contains the overall miles per gallon (MPG) of a type of vehicle. Complete parts a and b below. 29 23 32 33 22 20 20 23 24 27 43 23 30 25 Construct a 99% confidence interval estimate for the population mean MPG for this type of vehicle, assuming a normal distribution. The 99% confidence interval estimate is from ___ MPG to ___ MPG. (Round to one decimal place as needed.)
The data below represents the overall miles per gallon (MPG) of 2008 SUVs priced under $30,000. Complete parts a and b below. Start 2 By 1 Matrix 1st Row 1st Column 21 comma 20 comma 22 comma 23 comma 18 comma 19 comma 18 comma 16 comma 18 comma 20 comma 20 comma 2nd Row 1st Column 16 comma 22 comma 19 comma 16 comma 17 comma 16 comma 18 comma 16 comma 20 comma 15 comma 22 EndMatrix a....
The accompanying data represent the weights of various domestic cars and their gas mileages in the city. The linear correlation coefficient between the weight of a car and its miles per gallon in the city is r = −0.978. The least-squares regression line treating weight as the explanatory variable and miles per gallon as the response variable is ŷ=−0.0067x+43.2680. Car Weight (pounds), x Miles per Gallon, y 1 3,765 18 2 3,984 17 3 3,530 21 4 3,175 23 5 ...
The table below contains the overall miles per gallon (MPG) of a type of vehicle. Complete parts a and b below. 21 32 20 20 31 20 25 35 34 25 45 32 26 30 a. Construct a 99% confidence interval estimate for the population mean MPG for this type of vehicle, assuming a normal distribution. The 99% confidence interval estimate is from MPG to MPG Round to one decimal place as needed.) b. Interpret the interval constructed in (a)....
Cars > 1.5 tons Highway MPG (miles per gallon) 25 31 24 28 23 30 28 30 26 24 25 26 27 25 29 26 28 27 30 30 22 24 28 28 28 28 27 26 26 26 26 25 29 28 26 28 25 26 21 21 24 23 20 23 22 20 Find the standard deviation, quartiles and fences of the given data.
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...