Question

Three forces FA =141 lbs, FB =212 lbs and FH =58 lbs are acting on the bracket shown with axes x,y,v and w indicated. If the angle measurements on the figure are c=7o , d=18o , f=9o and g=14o, determine the magnitude (lbs) of the resultant force.

FA" NOTE: angles c, d, f, g, are not drawn to scale FH d X 00 W 'FB

Answer 1

FA = 1414, F₂ = 212 Lb FH = 58 lb c=1, d=18, fago, g = 14° - Resolving each force into two perpendicular components along x and y axis: Fi Fax =-FA cos((+) = -141 Cos(+18) = -127.79 us FA Sin (Ctd) = 141 sin(7418)= 59.59 lb FBx = - FB Cos (f+9)=-212 cos (9+14) =-195-15 is Fby = - FB sin(ftg) = -212 sin (9+14) = -82.836 FH: Frix = - FH = -58 Frey = 0 + 59.59 ŷ , ib Zo F = -127.79 is ? = 82.83 9 , is - 58i, is - 195.15 T4 -

Resultant ř ret + + E 8 = -380.94 ? - 23.25), u IF I = -380.94² + (-23:25) IF = 381.68 lb.