Question

For a 10 ft long A36 solid steel shaft with diameter equaling 4", undergoing a torque of 100,000 ft lb, what is the angle of twist? The Modulus of Rigidity/Shear Modulus of A36 steel is 11x10 psi. 0.0435 rad O 233 x 104 rad O 0.522 rad O 4.66 x 10-4 rad Question 26 Which of the following corresponds to positive internal shear, using the sign convention for shear/moment diagrams in our text? Question 27 Stress is maximum at the neutral axis. O True O False Question 28 The relationships between V, M, and w(x) include: O Change in Moment = the area under the distributed load diagram O dw/dx = V OdV/dx = w[x] Change in Shear= the area under the distributed load diagram OdM/dx = V OdV/dx = M Change in Moment = the area under the shear diagram

Answer 1

QUESTION : 1

The Solution for calculating angle of twist is given below as image file.

Question : 26

( ) L = loft = 3.048 on dall!! = Oil olbm. G = 11x ob psi = 6.89542090 m2 T = 1,00,oooftlb=13558 179Nm we know T GO T= I xd4 e 32 T = GOx J e 1. 3558xion 32 Hot = 6.895*209X OXIX (01016) 3.048 o=1.3558 2.365 o- o5rad Answer :-(C) + 0.522 ved

Option : 2 correspond to Positive Internal Shear

Question : 27

Stress is maximum at neutral axis is false. The stress will be zero at the neutral axis

Option : 2 False

Question : 28

The relationship between V, M and w(x) include the below option. I considered V as Shear force, M as Bending Moment. The Shear force at any section is equal to the slope of the bending moment diagram at that section. So, dM/dX = V is the correct answer.

Option (5) dM/dx = V. The Shear force