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For a particular reaction, AH° = -351 kJ, 45º = -236 J/K. Calculate AS of the...
For a particular reaction, AH° --351 kJ, AS --236 J/K. Calculate ASⓇ of the surrounding.
For a particular reaction, AH = -14.20 kJ/mol and AS = -198.5 J/(mol.K). Calculate AG for this reaction at 298 K. AG = 73.35 kJ/mol
A particular reaction has AH° = 55 kJ and AS = 101 J/K, at 25°C. A) Calculate the temperature (in K) at which AG° = 0. B) What is the significance of (what does it mean when or what does it indicate when) AGⓇ = 0?
For a particular reaction, AH = 27.58 kJ and AS = 284.6J/K. Calculate AG for this reaction at 298 K. AG = What can be said about the spontaneity of the reaction at 298 K? The system is spontaneous as written The system is at equilibrium. The system is spontaneous in the reverse direction.
AG°= AH-TAS AG=AGº+RTinQ where R=8.314 J/mol K 1. Calculate AGº for the following reaction at 25 °C if AH°= -1854 kJ/mol; AS°= -236 J/mol K CH-COCH3(g) + 402(g) → 3C02(g) + 3H2O(1) 2. NH.NO, dissolving in water is a spontaneous process. As it dissolves, the temperature of the solution decreases. Based on this, what must the signs (positive or negative) of AG, AH, and AS be?
For a particular reaction, AH = -16.1 kJ/mol and AS = -21.8 J/(mol-K). Assuming these values change very little with temperature, at what temperature does the reaction change from no to spontaneous in the forward direction? 5 T= Is the reaction in the forward direction spontaneous at temperatures s greater than or less than the calculated temperature? less than O greater than
M14. For a particular reaction, the enthalpy change is AH° = +100 kJ/mol and the entropy change is AS° = + 100 J/mol K. What is the equilibrium constant at 300 K?
For the reaction below, AH = -196 kJ and AS = -126 J/K at 25° C. 2H2O(1) + O2(g) → 2H2O2(1) Calculate AGº for the reaction in kilojoules. 0 -37.7 kJ -234 kJ -158 kJ -193 kJ -348 kJ
22 points For the reaction below, AH = -196 kJ and AS = -126 J/K at 25°C. 2H2O(l) + O2(g) + 2H2020) Calculate AG' for the reaction in kilojoules. 0 -348 kJ -37.7 kJ -193 kJ -234 kJ 0 -158 kJ Previous Next
For a particular reaction, ?H = -14.20 kJ and ?S = -198.5 J/K. 1)Calculate ?G for this reaction at 298 K. 2)What can be said about the spontaneity of the reaction at 298 K?