i started it but then i got lost, please correct me if im wrong! also, include sketch, thank u :)
i started it but then i got lost, please correct me if im wrong! also, include...
please include sketch, thanks! A discount brokerage selected a random sample of 64 customers and reviewed the value of their accounts. The mean was $32,000 with a population standard deviation of $8,200. What is a 90% confidence interval for the mean account value of the population of customers? Answers Point Estimate Standard Error Margin of Error Alpha Critical Value Confidence Interval
During a national debate on changes to health care, a cable news service performs an opinion poll of 490 small-business owners. It shows that 44% of small-business owners do not approve of the changes. a. Develop a 90% confidence interval for the proportion opposing health care changes. (Round your answers to 4 decimal places.) Confidence interval for the proportion:
1. A random sample of 82 customers, who visited a department store, spent an average of $71 at this store. Suppose the standard deviation of expenditures at this store is O = $19. What is the e 98% confidence interval for the population mean? 2. A sample of 25 elements produced a mean of 123.4 and a standard deviation of 18.32 Assuming that the population has a normal distribution, what is the 90% confidence interval for the population mean? 3....
6. A sample of size n- 200 has a known population standard deviation of 15.0. The population appears to be skewed. Determine whether a margin of error should be calculated using a critical value of za, a critical value of ta/2, or neither. Oa critical value of ta2 O a critical value of za O neither 7. The mean of a sample size n 35 is 1860. The standard deviation of the sample is 102 and the population is normally...
3. Fill in the blanks (show your work by drawing or using certain formula). a) (2 points) To form a 96% confidence interval for population proportion, 2.4 b) (2 points) To form a 98% confidence interval for population mean using a sample size of 26, to c) (2 points) For a 99% confidence interval with margin of error 0.03 with a prior estimate 0.65 of the sample proportion p in estimating population proportion p, we need to have sample size...
A) A certain region would like to estimate the proportion of voters who intend to participate in upcoming elections. A pilot sample of 25 voters found that 17 of them intended to vote in the election. Determine the additional number of voters that need to be sampled to construct a 95% interval with a margin of error equal to 0.06 to estimate the proportion. The region should sample ____ additional voters. B) Determine the sample size needed to construct a...
Question:The average cost per night of a hotel room in New York City is $472. Assume this estimate is based on a sample of 75 hotels and that the sample standard deviation is $54. a. At 90% confidence, what is the interval estimate for the population mean? b. At 95% confidence, what is the interval estimate for the population mean? c. At 99% confidence, what is the interval estimate for the population mean? d. Describe the effect of a higher...
Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard deviation s=25 (population standard deviation is not known) Estimate confidence interval for population mean with confidence level 90%. Confidence Interval = Sample Mean ± Margin of Error Margin of Error = (t-value)×s/√n t-value should be taken from Appendix Table IV. For n=9 df=n-1=9-1=8 For Confidence Level 90% a = 1 - 0.90 = 0.10, a/2 = 0.10/2 = 0.05 So, we are looking for...
I recommend that you practice using the standard Normal tables to calculate zα/2 and tα/2 . Costs are rising for all kinds of health care. The mean monthly rent at assisted-living facilities was recently reported to have increased 15% over the last five years. A recent random sample of 120 observations reported a sample mean of $3563. Assume that past studies have informed us that the population standard deviation is $650. For this problem, round your answers to 2 digits...
8.1.5 Question Help Determine the 95% confidence interval estimate for the population mean of a normal distribution given n = 100, o = 133, and x = 1,500 The 95% confidence interval for the population mean is from to (Round to two decimal places as needed. Use ascending order.) 8.1.14-T Question Help As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage for their vehicles. A simple...