Question

in the circuit below. the emf of the battery e= 14volts, and the resisto has values r= 192 R2=141 R3=185 R4=198. what is the current supplied by the battery to this circuit? Answer to the nearest milliamps (1000 milliamps =1amp)

Post Attendee - Zoom University of Minnesota 22120BEGDO 2 pts Question 1 In the circuit shown below, the emf of the battery E-19 volts, and the resistors have values R1 - 179 2. R2 - 106 12. R3 - 183 and RA - 128 2. What is the current supplied by the battery to this circuit? (Hint: first find the equivalent resistance of the circuit.) Answer in milliamps to the nearest milliamp, where 1000 milliamps = 1 amp R3 E R R 법 R 2 pts Question 2 In the circuit shown below, the emfs of the batteries are E1=41 volts, E2=20 volts, and E3=32 volts; and the resistors have values R. = 330 and R. = 48 0 Initially 30

Answer 1

Question emf of the battery E = 19.00hs R, 19 2 R2= 106 2 183 R 1 Rz RA 128 2 This circuit can be simplified R .R -> &3 RA Rq So , R₂ and Rg. are in series R2 is Parallel with R3 t Ry equivalent resistance of R3 and Rq is R₂ + Rq (183 + 128) so, .311 ri R₂ x 311 r. So, م Now, This is parallel with Re.. eanivalent resistance = (R2+311) 106 X 311 (106+311) 79.055 r. now, this is in series with RI so, Net equivalent resistance = 179 + 79.055 258.055 R. so the (wirent suppried (I) = 28. 258.055 19 258.055 Current (2) = #3.6 MA 0.0736 A = 73.6 MA - 11