Question

Coherent electromagnetic waves with wavelength pass through a narrow slit of width a. The diffraction pattern is observed on a tall screen that is 2.00 m from the slit. When X=500 nm, the width on the screen of the central maximum in the diffraction pattern is 8.00 mm Part A For the same slit and screen, what is the width of the central maximum when = 0.125 mm? Express your answer with the appropriate units. НА ? 2y = Value Units Submit Request Answer Provide Feedback

0.125 mm is wrong btw

Answer 1

We know width of cental maximum gy = do = ware leneth o= screen distance d =slit width 1) 2g = dip d dao Divide d by 0 242 241 so 2 - 12 x 291 de 125 X 8 50 942 - 2 mm