samplex Problem1: Solve the following problem using simplex method: Max. z = 2 x1 + x2...
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Problem 3. Solve the following LP by the simplex method. max -x1 + x2 + 2xz s. t x1 + 2x2 – x3 = 20 -2x1 + 4x2 + 2x3 = 60 2xy + 3x2 + x3 = 50 X1, X2, X3 > 0 You can start from any extreme point (or BFS) that you like. Indicate the initial extreme point (or BFS) at which you start in the beginning of your answer. (30 points)
Use the simplex method to solve this problem Objective Function (OF) Max Z = 5x1 + 3x2 + x3 Restrictions x1 + x2 + x36 5x1 + 3x2 + 6x315 Xi0
Q3. (Dual Simplex Method) (2 marks) Use the dual Simplex method to solve the following LP model: max z= 2x1 +4x2 +9x3 x1 x2 x3 S 1 -x1+ X2 +2x3 S -4 x2+ X1,X2,X3 S 0 Q3. (Dual Simplex Method) (2 marks) Use the dual Simplex method to solve the following LP model: max z= 2x1 +4x2 +9x3 x1 x2 x3 S 1 -x1+ X2 +2x3 S -4 x2+ X1,X2,X3 S 0
2. Consider the following LP: Min z = -4x1 - 5x2 + 3x3 Subject to X1 + x2 + x3 = 10 X1 X2 > 1 X1 + 3x2 + x3 = 20 X1, X2, X3 20 (a) Solve the problem by Big M method. (b) Solve the problem by two-phase method.
Using the dual simplex, please solve the following linear program min z = x1 +x2 s.t. 2x tx2 5 2x1 + 3x2 26 (all x's are nonnegative) Using the dual simplex, please solve the following linear program min z = x1 +x2 s.t. 2x tx2 5 2x1 + 3x2 26 (all x's are nonnegative)
Solve the linear program using the simplex algorithm method maximize Z = 5x1 + x2 + 3x3 + 4x4 subject to: x1 – 2 x2 + 4 x3 + 3x4 s 20 –4x1 + 6 x2 + 5 X3 – 4x4 = 40 2x1 – 3 x2 + 3 x3 + 8x4 5 50 X1, X2, X3 , X4 20
Excel Use Simplex method and Exel To solve the following LPPs. Maximize Maximize P-3x + x2 subject to the constraints x1 + x2 = 2 2x) + 3x2 s 12 3x + = 12 x 20 x220 P = 5x1 + 7x2 subject to the constraints 2xy + 3x2 = 12 3x + x2 = 12 x 20 *2 2 0 Maximize Maximize P = 2x2 + 4x2 + x3 subject to the constraints -*1 + 2x2 + 3x3 5...