Question

Question 22 Not yet answered Points out of 8.00 Flag question The figure shows two parallel loops of wire having a common axis. The smaller loop (radius r) is above the larger loop (radius R) by a distance x >> R. Consequently, the magnetic field due to the counterclockwise current i in the larger loop is nearly constant throughout the smaller loop. R (a) Find an expression for the magnetic flux through the area of the smaller loop as a function of i. Select one: a. HR2,2 2²+R2 . b HR2,2 c. ? d. BA e. Hoit 2²+R2

Answer 1

Magnetic field at Small Coop due to large loop is is given by B - HoiR? 2 (x2+R2) 32 But giver x»R, hence x² R² = x2 . B-MoiR? 2x² Now, flum , & - BA - HoiR? 2x² x ūga Mo i TT R²2 2x3

23) flux, Q = Mollir?? 2x3 Induced emf do Monir? d (8²) dt 2x3 dt Mahir&28 dr 2x3 dt Moili R² di dt x3 24) Clockwise direction using lenges law and right hand sulle.