Solution:-
Consider the equation of a line
2x + 3y = 7.
Let us convert it into slope intersect form.
2x + 3y = 7
3y = -2x +7
y = -2x/3 + 7/3
So, slope of this line is m' = -2/3 (on comparing with standard slope intercept form of an equation of line y = mx +c ).
Now, slope of a line(m) perpendicular to this given line is negative reciprocal of m'.
So, m= -1/m' = -1/(-2/3) = 3/2
We know that equation of line passing through (a, b) having spope m is
y - b = m(x - a)
So, equation of line passing through (2, -5) and having slope 3/2 is
y - (-5) = (3/2)(x - 2)
y + 5 = (3/2)(x -2).
Hence, the equation of line perpendicular to given line and passing through (2, -5) is
y + 5 = (3/2)(x -2)
(Correct option - a)
22, 22, which equation can be used to find the equation of a line that passes...
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