Question

A new study of 140 lung cancer patients found that 129 of them died within a year, while undergoing a new treatment. Based on this sample data, compute 98% confidence limits to complete the statement below. Use Normal distribution instead oft: E= 2a. PG n za v Give values as percentages, rounded to two digits after the decimal point. Do not include the % symbol in your answer. Number percent of lung cancer We are 98% confident that between Numbel percent and patients undergoing the new treatment will die within a year.

Answer 1

Answer : ( 86.84 , 97.43) or use ( 87,97) percent

ti -84 output

X = 129 na 140, c-level = 98% X p = 129 -0.9214 140 Critical value for 98% confidence interval Zca 2.33 d-1-0.98 = 0.02 of 20.02/2 = 0.01 Area - 1-0.01 -0.99 Icheck 0,99 areal Confidence interval formula ľ 1 c Ê CI- n 0.9214 t 2.33 0.9214Cl-0.9214) 140 0.9214 2.83 0.000517 0.9214t 0.052994 C 0.9214-0.052994, 0.9214+ 0.052996) C 0.868 4,0.9743 ) To convert percent multiply by 100 (86.84, 97.43) We are 98% confident that between 86 86.84 percent and 97.43 percent of lung cancer patients undergoing the new treatment will die within a yeare.

1-Propzont (.86853,.97433) P=.9214285714 n=140