Question

1. If a random employee is chosen, the probability of selecting an employee who tests positive or who uses drugs is 2. If two
drug tests were carried out on company employees and the results are summarized in the following table. Negative test result
The following table represents the probability distribution of a discrete variable x. What is the value of the unknown probab
P(x) 0 0.12 0.05 1 2. 0.24 3 P(3) 0.18
0 0
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Answer #1

1. Probability = (5/50)*(45/50) = 0.09

2. 0.12 + 0.05 + 0.24 + P(3) + 0.18 = 1

P(3) = 1 - (0.12 + 0.05 + 0.24 + 0.18) = 0.41

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