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A 89g piece of lead was heated up to 285C and put into 400mL of water (at 15C). What is the final temperature of the lead? (3

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Answer #1

17 °C

water Heat lost by lead = Heat gained b AT) lead in Cat) water (me z 89 x.130 x (285-T) = 400 x 4.2x (T-15) 285-T = 145,2 T 2

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