Solve the system X1 + 2x2 – 3x3 = 5 2x1 + x2 – 3x3 = 13 - X1 + x2 = -8 [1 X=t1 tec 1 a. b. SEC Oc. 1 - -- 1. Jeee -2 -0. x=t0 O d. -1 , SEC e. SEC o f. X=S 2 3 ], sec -5
Solve the system X1 + 2x2 - 3x3 = 5 2x1 + x2 – 3x3 = = 13 - X1 + X2 = -8 O a. x= 1, SEC 0 Ob. tec x=1 1 Ос. 2 x= 3, SEC -5 0 d. 1 x=0 -1 gree -1 SEC x=s -1 0 Of. 1 X=S 0 -1 SEC 0
Solve the system a. b. c. d. e. f. Solve the system X1 + 2x2 – 3x3 = 5 2x1 + x2 – 3x3 = 13 - X1 + X2 -8 2 X=S 3 SEC -5 a. b. 1 x=t0], tec x=s -1 SEC d. 1 x= t 1 tec 1 e. O 1 0 X=S SEC -1 0 o f. 1 SEC x=s 1 0
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination x1 + 2x2-3x3 = 19 2x1 -X2+ X3 - 4X1- x2 + x3= 8
Consider the following LPP: Maximize z = 50x1 + 20x2 + 30x3 subject to 2x1 + x2 + 3x3 + 90 (Resource A) x1 + 2x2 + x3 + 50 (Resource B) x1 + x2 + x3 + 80 (Resource C) x1, x2 , x3 > 0 The final simplex table is Basis cj x1 x2 x3 s1 s2 s3 Solution 50 20 30 0 0 0 x1 50 1 -1 0 1 -1 0 40 x3 30 0...
Problem 1 (20 pts) Consider the mathematical program max 3x1+x2 +3x3 s.t. 2x1 +x2 + x3 +x2 x1 + 2x2 + 3x3 +2xs 5 2x 2x2 +x3 +3x6-6 Xy X2, X3, X4, Xs, X620 Three feasible solutions ((a) through (c)) are listed below. (0.3, 0.1, 0.4, 0.9, 1.65, 1.6) (c) x Please choose one appropriate interior point from the list, and use the Karmarkar's Method at the interior point and determine the optimal solution. 25 Problem 1 (20 pts) Consider...
1. Find all solutions to the system x1 + 2x2 + 3x3 = 8 1 x1 - x2 + 3x3 = 5 =>{801_ ) but ke 2. Is a basis for R3? 13 12
3. Solve the following system of homogeneous equations 2.x1 + x2 + 3x3 = 0 x₂ + 2x2 x2 + x3
Consider the mathematical program max 3x1 x2 +3x3 s.t. 2X1 + X2 + X3 +X4-2 x1 + 2x2 + 3x3 + 2xs 5 2x1 + 2x2 + x3 + 3x6 = 6 Three feasible solutions ((a) through (c)) are listed below. (b) xo) (0.9, 0, 0, 0.2,2.05, 1.4) (c) xo) (0.3, 0.1, 0.4, 0.9, 1.65, 1.6) Please choose one appropriate interior point from the list, and use the Karmarkar's Method at the interior point and determine the optimal solution.
2x1 − x2 − 3x3 − 2x4 = 1 x1 − x2 − 4x3 − 2x4 = 5 3x1 − x2 − x3 − 3x4 = −2 x1 + 2x3 − x4 = −4