Question

A mass M slides upward along a rough plane surface inclined at angle = 0.16 in radians to the horizontal. Initially the mass has a speed Vo = 2.68 m/s, before it slides a distance L = 1.0 m up the incline. After sliding this distance the new speed of the mass is V /4 measured in m/s. What is the acceleration of the sliding mass? (Positive denotes acceleration up the incline; negative denotes acceleration down the incline.)

Answer 1

$\theta$ = 0.16 rad = 9.167 degree

v_o = 2.68 m/s

v_f = 0.67 m/s

L = 1 m

so,

v_f² - v_o² = 2aL

0.67² - 2.68² =2 * a * 1

so,

a = - 3.366 m/s²