Question

QUESTION 2 For the point charges shown below, use the coordinate system indicated. ke -9.00 x 10°N-m2/C2 = 8.85 x 10-12 CZ/N m2 q2= -3.00 LC 35.0 cm q1=2.00 uc 20.0 cm 60.0° 25.0° P a) What is the electric field at point P due to charge 1 ONLY, in unit vector notation? b) What is the total electric field at point P due to both charges, in unit vector notation?

Answer 1

Electric field at p due to charge qı can be calculated as follows: Ēa =-&, cos 25*1- €, sin 25 ) cos 25i – k, 91 sin 25 2 Racos 2 k.91f-cos 25'i – sin 25 i] 9x 10° Nm2 (2x100c). [-cos 25*î– sin 25"}] (0.2m) = 4.5x10º[-(0.9063)**-(0.4226) j] (4.08x10-):- (1.90x10")) Therefore, out of all the correct option is → B* b→ Electric field at p due to charge 4, can be calculated as follows: En =-Ecos 60'î +€, sin 60%) =Kqz [-co $ 60*î+sin 60"}] 10. Pema) == 9x 10° (3x10 C). | -cos 60°î+ sin 60°] (0.35 m) --(1.10x10) +(1.9087x109) Total intensity at point p due to the charges q&q is, E = Eq, +42 =[-(4.08x10*)- (1.90x10)]+[-(1.10x10$){+(1.9087x10°)] -(5.1810*)i+(1.00x10°) Therefore, out of all the correct option is → I