Question

For the point charges shown below, use the coordinate system indicated. ke -9.00 x 10° N-m2/C2 20 -8.85 x 10-12 C21N-m2 q2= -3.00 °C 35.0 cm q1=2.00 uc 20.0 cm 60.0° 25.0° OD. a) What is the electric field at point P due to charge 1 ONLY, in unit vector notation? b) What is the total electric field at point P due to both charges, in unit vector notation? OA The field from charge 1 is E7 - 4.08 x 105 i+ 1.90 x 105; B. The field from charge 1 is E1 - --4.08 105; -1.90 x 105; OC The field from charge 1is E1 - 8.16x 104 1 + 3.80 x 104; The field from charge 1 is E1-.8.16 x 104 ; - 3.80 x 104; DE. The field from charge 1 is E1 - 0.203 i + 0.199j OF The total field is E - 5.10 x 105, + 3.81 x 105; D G The total field is E = 1.06 x 1051 + 7.06 x 104; OH The total field is E -- 5.10 x 105; -3.81x105; OL The total field is E-.5.18x105 +1.00 103; The total field is E-.1.06 x 1051.7.06 x 104,

Answer 1

The magnitude of the electric field due to charge q, is, ka, = E = ri (9.00x10°)(2.00x100) (0.20) = 4.5x10'N In vector notation, Ē, =-E, cos 25(i) – E, sin 25(j) -4.08x10° (i) -1.90x10' (1) The magnitude of the electric field due to charge q, is, = ka2 E2 II

(9.0010)(3.00×10) (0.35) = 2.20 x10 N In vector notation, Ēx =-E, cos 60(i)+E, sin 60(j) =-1.10x10$ (i)+1.91x10ʻ(j) Thus the net electric field is, Ē = Ē, +Ēj =-4.08x10°(i)-1.90x10ʻ(j)+-1.10x10ʻ(i)+1.91*10*(j) = -5.15x10° (i)+1.00×10 (3)