Question

Two points A and B are near a point charge as shown below. Ke = 9.00 x 109 N-m2/C2 80 = 8.85 x 10-12 c2/N-m2 A 15.0 cm 25.0° B -4.00 uC 25.0 cm a) What is the difference in electric potential VB-VA? b) What is the change in potential energy for moving a-3.00 uC charge moved from A to B? A. The difference in potential is 1.02 x 106 V The difference in potential is -1.02 x 106 V OC. The difference in potential is 9.60 x 104 v U U The difference in potential is -9.60 x 104 v E. The difference in potential is none of these answers The change in potential energy is -3.06 ) F. 0 OG The change in potential energy is 3.06 ) The change in potential energy is none of these answers U I. 0 The change in potential energy is 0.288) J. The change in potential energy is -0.288 )

Answer 1

O. MB: 25cm sb: 0.25m SA 15 cm - 0.15 m MA: 15cm ke-9x109 Nm/? J25° - 440 25cm rB cet Electric potential ang point P is given as, Ke o Up = 1 x oi 4o ai where o is charge and his distance of point from charge. SIA : botant Given that, O=-4HC .. Potential at point A. VA=ke. O =Y VA = 9610x+4) x 10-6 v 0.15 =Y TVA --240000 V Potential at point B. UB=ke o MB :. diffee erence = UB= 9610% (-4)x10-6 0.25 - 144000 V UB- Up - [144000-(-240000) Ju - 9600oV in electric potential, Vo- VA = 96000 V -> IVA-VA= 9.6x1040 Given that -3HC charge mou is moved from A to B , ie., q=-3HC b

Potential energy of charge at point f is. UA : qUA Potential energy of charge at point B is, Ub= que Differe change in potential energy as charge is moved from A to B is, Ou: UB-UA ..ou= q UB-QUA => Du= q (UB-VA) =Y OU=(-3x10-6 96000)J & Tour change in potentiale energy charge moves from A to B is -0.2885 Hence solution is, Potential cobference, VB - VA = 9.60x1040] coption () o change in bertential energy, bu=-0.288coptions) 0:288 J са