Question

PLEASE FAST I HAVE 15 MINS LEFT !!

Question 1: [50 Marks] For the frame shown, draw the bending moment diagram for each member. 40 kN/m 60 kN E D 80 KN 3 m 540 kN.m С B 3 m A 1.5 m 3 m

Answer 1

40 kN/m E Mat Eco 60 kN En D 80 KN 3 m Ayx3 - 80x4.5-40x3x1.5 +520 =0 540 kN.m с B 3 m Ay=o, A Efy=o, yox3 + go = 200 kn Ey = Tay 1.5 m 3 m for member CB Bending moment of be 80KN M B 80X105 = 120 KN-n 1.5m G 80 KN - Ma= - 800 -120 kNm n. for AD Bending of AD 420kn C J 3m o B 4 20 KN 540-120 = 420 KN 3m 4 40 M A

х ОС 420 4Okn-m н и 2 от ky gok 42km) In ра 3 м. Mr = а 420 – goy — ҷо - Х., Х 80 kNm Мя - +20 – 80х- 2ox- 42o km (kam Ф) G V Р 3 m