By energy conservation, total of KE and PE of the proton is conserved.
1. A proton has a speed of 1.5 x 10 m/s at a point where the electrical potential is 1000 V. It moves through a point where the electric potential is 900 V. What is its speed at this second point? (e = 1.60 x 10-19, mproton = 1.67 * 10-27 kg) 3.55 x 10 m/s 0.53 * 10 m/s 2.04 * 1010 m/s 2.04 x 10 m/s 04.16 1010 m/s
1. A proton has a speed of 1.5 x 109 m/s at a point where the electrical potential is 1000 V. It moves through a point where the electric potential is 900 V. What is its speed at this second point? (e = 1.60 x 10-19, mproton = 1.67 x 10-27 kg) 4.16 x 1010 m/s 2.04 x 10'0 m/s 02.04 10 m/s O 0.53 x 10ʻm/s 3.55 x 10 m/s
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve? A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
A proton is moving at a speed of 1.5 x 10^5 m/s when it travels through a potential difference and accelerates uniformly to a speed of 4.5 x 10^6 m/s. What was the value of the potential difference through which the proton traveled. If the distance the proton traveled was 50 cm, what was the magnitude of the electric field?
If a proton m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is released from rest at the + plate in the below electric field, what will be its speed at the-plate? 3 cm E = 5000 N/C
A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg) A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)...
A proton (m, = 1.67 X 10-27 kg, qo=e= 1.60 X 10-19 C) and an alpha particle (me = 4m, 9a= 49p) start from rest at the same point in a region of uniform electric field E= 200 V/m. Each particle travels a distance of 4.0 cm in this field. (a) At that point, which particle has the higher kinetic energy, and what is this energy? (b) At that point, which particle is moving with the higher speed, and what...
A constant electric field accelerates a proton from rest through a distance of 1.65 m to a speed of 1.81 ✕ 105 m/s. (The mass and charge of a proton are mp = 1.67 ✕ 10−27 kg and qp = e = 1.60 ✕ 10−19 C.) HINT (a) Find the change in the proton's kinetic energy (in J). J (b) Find the change in the system's electric potential energy (in J). J (c) Calculate the magnitude of the electric field...
A constant electric field accelerates a proton from rest through a distance of 1.65 m to a speed of 1.77 ✕ 105 m/s. (The mass and charge of a proton are mp = 1.67 ✕ 10−27 kg and qp = e = 1.60 ✕ 10−19 C.) HINT (a) Find the change in the proton's kinetic energy (in J). J (b) Find the change in the system's electric potential energy (in J). J (c) Calculate the magnitude of the electric field...
particle electron: proton: charge mass me = 9.11 × 10-31 kg me = 1.67 × 10-27 kg m, = 1.67 × 10-27 kg 9e =-1.60 × 10-19 C = +1.60 × 10-19 C neutron: Coulomb's law: F = kelellel/r2 where ke = 8.9875 × 10" N m?/C". Electric field: E = F/go- Electric field of a point charge: E kell/r2. 1. Sketch the electric field of a pair of oppositely charged particles.