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A proton (m, = 1.67 X 10-27 kg, qo=e= 1.60 X 10-19 C) and an alpha particle (me = 4m, 9a= 49p) start from rest at the same po

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Answer #1

a] Kinetic energy = decrease in PE

= qE*d

Alpha particle has larger KE because of larger charge.

KE = 2*1.6e-19*200*0.04

= 2.56*10^-18 J

b] speed v = sqrt(2a*d)

d is same for both, but acceleration a of proton is larger as a=qE/m and for alpha a=2qE/4m

so speed of proton is higher.

v = sqrt(2*1.6e-19*200/1.67e-27*0.04)

= 39153 m/s

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