In a vacuum, a proton (charge = +e, mass = 1.67 x 10-27 kg) is moving...
In a vacuum, a proton (charge = +e, mass = 1.67 x 10-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +4.40 x 104 m/s and accelerates in the same direction as the electric field, which has a value of +7.90 x 103 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. +2.0 mm...
In a vacuum, a proton (charge = +e, mass = 1.67 times 10^-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +4.30 times 10^4 m/s and accelerates in the same direction as the electric field, which has a value of +5.70 times 10^3 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. Number Units...
A proton (mass = 1.67 x 10-27 kg, charge = 1.6 x 10-19 C) released from rest inside a uniform electric field undergoes a displacement of 0.30 meters. The electric field has a magnitude 8.0x104 V/m, along the positive x-axis. a) What is the potential difference experienced by the proton? b) What is the the change in the electric potential energy of the proton due to this displacement? (pay attention to the sign). c) What is the spoed v of...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.60e+3~N/C N/C . The region of uniform...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.35e+3~N/C N/C . The region of uniform...
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...
(#966932-48) (Motion of Charge in Field) D2 (Motion Perpendicular to Field) A proton of mass mp-1.67 × 10-27 kg and a charge of gp-1.60 x 10-19 C is moving through vacuum at a constant velocity of 10, 000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of El =2.83e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How...
PLS ANSWER THIS ASAP I WILL RATE proton (mass 1.67*10^ ^ -27 , charge ^-19 C) is placed in a uniform electric field. The proton undergoes an acceleration of 10^ ^ 11 m/s^ ^ 2 A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field. The proton undergoes an acceleration of 10^11 m/s^2. a) What is the magnitude of the electric field? b) If the electric field is produced by two large parallel plates connected...
A proton (m, = 1.67 X 10-27 kg, qo=e= 1.60 X 10-19 C) and an alpha particle (me = 4m, 9a= 49p) start from rest at the same point in a region of uniform electric field E= 200 V/m. Each particle travels a distance of 4.0 cm in this field. (a) At that point, which particle has the higher kinetic energy, and what is this energy? (b) At that point, which particle is moving with the higher speed, and what...
A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z- axis at (x,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.67 m in the x-direction. The proton leaves the field having a velocity vector (Vx, vy) = (2.6 X 105 m/s, 1.2 X 105 m/s). V ---D---- 1) What is v, the...