Question

A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z- axis at (x,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.67 m in the x-direction. The proton leaves the field having a velocity vector (Vx, vy) = (2.6 X 105 m/s, 1.2 X 105 m/s). V ---D---- 1) What is v, the magnitude of the velocity of the proton as it entered the region containing the magnetic field? m/s Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What is R, the radius of curvature of the motion of the proton while it is in the region containing the magnetic field? m Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) What is h, the y co-ordinate of the proton as it leaves the region conating the magnetic field? m Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 4) What is Bz, the z-component of the magnetic field? Note that Bz is a signed number. T Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 5) If the incident velocity v were increased, how would h and change, if at all? Oh and would both increase Oh and would both decrease Oh would increase and would decrease Oh would decrease and would increase ONeither h nor would change Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. (Survey Question) 6) Below is some space to write notes on this problem.

Answer 1

(LeU) origih centre of corvetul Rcoso R (ope o magnetic field changing only direction of charge particle Magnetic field do not change Maghetude of velocity se v=j ur + vy? o = Ja G2+ (1-22 x 105 Tu= 2.86 x 105 m/sec To calculate Radius of curvature • for circulen motion qVB 2 = muk - 2 mu mv qBz from diagram tanto (0 = 24.770 sino = 2 » RF The " IR = 1.6om l 4 from Eqh ① Bo mo 1067X10 27x2086x105 B2 = 10868.10 3 Tesla