Find magnitude and direction
Net force, F 2=82+62 N
F2=100 N and hence, F= 10N
Acceleration, a = F/m= 10/5= 2m/s2
If the net force F makes an angle beta(b) with the horizontal, then the acceleration will also make an angle beta (b) with the horizontal. this is because the acceleration is always in the direction of the force.
Tan b = 6/8 =3/4 = 0.75
Hence, b = tan-1(0.75)= 36.9o
A body of mass 5kg is acted upon by two perpendicular forces of magnitude 8N and 6N. Find the magnitude and direction of the acceleration
A ball, with a mass of 5kg, accelerates in the +x direction with a magnitude of 5m/s^2 and in the -y direction with a magnitude of 2 m/s^2. 1. What is the acceleration vector that describes this motion? 2. What is the net force vector on this ball? Hint: Use Newton's 2nd Law!
3. An object is acted upon by two forces of magnitude 10N and 8 N at an angle of 60° to each other. Draw the two vectors and the resultant. [15.62N at 26.33º to the 10N force]
find 1) F2 (magnitude & direction) 3) E2 (magnitude & direction) 2) F1 (magnitude & direction) 4) E1 (magnitude & direction) 32 31x 30° 0 30° 02 +50 uC 52 cm P.S. SHOW ALL WORK. MAKE SURE YOU PUT ALL FORCES DIRECTION ON THE ABOVE DIAGRAM
A trolley that moves along a horizontal beam is acted upon by two forces as shown. Determine by trigonometry the magnitude and direction of the force P so that the resultant is a vertical force of 2.5 kN.
Two vectors:
Find the magnitude and direction for the resultant vector
The magnitude R =
The Direction =
Write your answer as integers
A=4 Ñ +7 B= 8 -29 We were unable to transcribe this imageWe were unable to transcribe this image
The magnitude and direction of two forces acting on an object
are 80 pounds. S50 degrees E, and 110 pounds, N76 degrees
E,respectively. Find the magnitude, to the nearest hundredth of a
pound
The magnitude and direction of two forces acting on an object are 80 pounds, 550°E, and 110 pounds, N76°E, respectively the nearest tenth of a degree of the resultant force. The magnitude is approximately 169.83 pounds (Do not round until the final answer. Then found to the...
A trolley that moves along a horizontal beam is acted upon by two forces as shown. Determine using the parallelogram law or the triangle rule the magnitude and direction of the force P so that the resultant is a vertical force of 2500 N 1600 N
the true magnitude and direction of the support forces A and B Find 1000lb -150lb/f 100lb/ft 6" 8 EQUIBLIUM ANALYSIS EQUIBLIUM ANALYSIS DIAGRAM OF TRUE MAGNITUDE AND DIRECTION OF THE APPLIED FORCES AND THE SUPPORT REACTIONS AT A ANDB
What are the magnitude and the direction angle of the vector (V21,2)? (Find the direction angle in degrees rounded to the nearest tenth.) The answer is O A. The magnitude is 25 and the direction angle is 66.4°. O B. The magnitude is 5 and the direction angle is 66.4° O C. The magnitude is 25 and the direction angle is 23.69 OD. The magnitude is 5 and the direction angle is 23.6º.
Click here to watch the video The magnitude and direction of two forces acting on an object are 120 pounds, S53°E, and 110 pounds, N55°E, respectively. Find the magnitude, to the nearest hundredth of a pound, and the direction angle, to the nearest tenth of a degree, of the resultant force The magnitude is approximatelypounds (Do not round until the final answer. Then round to the nearest hundredth as needed.)
Click here to watch the video The magnitude and direction...