Question

A brittle material has the properties Sat 19 kpsi and Suc 95 kpsi. Using the brittle Coulomb Mohr and modified Mohr theories, determine the factor of safety for the following 0x = 18 kpsi, Gy = 14 kpsi, Txy 0 Hint: Coulomb-Mohr Theory: Oxt Oy 2 + + If A 2 0820 A = Sut If 0 202 03 OA Sut Suc Suc If 0 2 042 OB ов a. n-1.22 b. n - 2.72 Ocn- 3.14 Od.n - 1.52 en-1.70

Answer 1

TAR = oxtoy + JA), OB>O Sut= 49 kpsi , Suc=g5kpsi 5x = 18kpsi , Gyat Alpsi Zxy=0 Then pridacipie stresses Coa406) JA&B= 18+14 (18-14)²+(012 TABOB = A = 16+2 = 18 kpsi B = 16-2 = 14Kpsi here y tex3]2 2 2 16 t2 then JA = Sut is applicable factor of safety na Sut TA n= 49 =2.72 18 option b n = 2.72