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A photon of wavelength 3.48 pm scatters at an angle of 107∘ from an initially stationary,...

A photon of wavelength 3.48 pm scatters at an angle of 107∘ from an initially stationary, unbound electron. What is the de Broglie wavelength of the electron after the photon has been scattered?

de Broglie wavelength: ______pm

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Answer #1

327/38 a = 3.48pm, 0107 ^. = (1-coso) -34 Al -12 3.48X to F 6.626x10 C os (102) 8 9R10 x 3x10 -12 6.62 x 10 according to conv

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