Question

Tarzan (mı = 90.0 kg) is perched on a cliff 16.0 m above Jane. Answer the three questions below, using three significant figures. Part A: What is the value of Tarzan's speed (Vr) just as he gets down to Jane's level? VT = m/s Part B: If Tarzan is actually moving at 10.5 m/s, what fraction (%-loss) of kinetic energy did he lose due to air resistance? %-loss- % Part C: If Tarzan's mass were 40 % greater, how would that affect the answer for Part A? His speed would be

Answer 1

Coering energy between position A & Taazan 1 A IGM jang P.E=0.- 13 (K.E+PEJA = (KE+P. Els I mxo²+ mgxlbm bm= 2 mu?+ mg xo > -> img xlbm = mu? 9.62 29x16m = e =12x9.8m/s2*16m v-17.708 misto y Jh an Bon e = 177 ml (3-sigenificant digite) (B) of itsee at B is 10.5 m/s KiE Lors = ² mx 17.7m/s² m 10.5} speed Žm [(77m/s) ² (10.5 m/s)? - fraction of KE Loss = Žm [(17.7m/s)²-(10.5916)] tam (17.7m/s) -

fraction of K E Loss = 0.649 >> % % loss = 64.9% AM (C) As answer of part A ze. Speed zs tindlupen endent of mass of tarzan, increase in mass won't arrect the the speed would remain speed. Hence the same Am