Question

Tarzan (my 95.0 kg) is perched on a cliff 14.0 m above Jane. Answer the three questions below, using three significant figures. Part A: What is the value of Tarzan's speed (Vr) just as he gets down to Jane's level? VT = m/s Part B: If Tarzan is actually moving at 11.0 m/s, what fraction (%-loss) of kinetic energy did he lose due to air resistance? %-loss = Part C: If Tarzan's mass were 40 % greater, how would that affect the answer for Part A? His speed would be

Answer 1

Paro By A). conservation P. Ereight energy Koko at migh = / my ve reaching Tane 2 2. Vy zgh uy = 52gh » j 2x9.88 14 V 52x908814 mis V = 16.56 m/s PAREB) The kinetic energy will theoretically willl be cally calcula K.Eth 2 m, v2 Now achial Kinetic energy will be Kof.a : - ma va? So fraction loos (o/o less) will be k. Eth - Kota Keith X 180

of loss & 2) I my vy 2 - I ma Ś my vy? N, 2 - Va² 3 V72 9 274.4 - 121 A 100% 274.4 V Oo 5 593 8100% % loss 쇠 55.93 70 Parte) as we have seen that the velocity I tarzan i dependent 2 factors On mass I tarzan Vq 2 J 2 gh It ů independent of increase in mass will make difference So So the W On the velocity to orect option is 3 )