Question

QUESTION 7 A prism made of saphhire with a refractive index of 1.762 is immersed in oil with a refractive index of 1.390. Light initially traveling horizontally in the oil enters the prism as shown below. 60.0° a) What is the refracted angle inside the prism? b) What is the refracted angle when the light exits the prism?

Answer 1

Option B and H are correct. For explanation please find the attachment.

12 We know from the snell's law of refraction at an boundary ni sindi = nr sinor ni = Refractive index of incident medium Retracted . Dy = 21 2. Qiz Angle of incident Angle of refractim. 2

30 90-Or E 60 Og n = 1.390 no = 1762 .09 8 From the above fig Q: +60° = 90° 309 . mi 1.390 My = 10762 no sinora nix sindi 1.390x sin 30 = 0.695 sinor 0.695 1.762 h68.0 = Org sim! (0.394) = 23:20

Now for the triangle <cor go - Orn 90 - 23.2 66.2 :. (CFD 180 - 30 - 66.8 - 83.29 itora angle of (neident at plomo BC O: 90 - 832 6.89 ? No sinora E nisin oi 1.762x sin (6.2.) 0. 205 sinor 0205 1.390 0.147 DY sin -4 (0-147) = 8:49 and I are eoreet. optim B