Question

​In the optical fiber below, the core has a refractive index equal to 1.5


In the optical fiber below, the core has a refractive index equal to 1.5 and a cladding of refractive index of 1.4.


 a) What is the speed of light inside the core?

 b) What is the critical angle at the core-cladding interface?

 c) What is the maximum angle "t" that the rays leaving the source of light should make with the axis of the fiber so that total internal reflections takes place at the core-cladding interface? 


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Answer #1

solution - (a) speed af light inside the core = v = ncore a 9.0x108 m/ = 9:0x108 mis - 3.0x10 210x108 (b) Critical angle = 0e

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