The numerical aperture can be calculated using the formula NA = Sin(22) where 22 is abgle of acceptance, so the NA comes out to be -0.008513092
the cirtical angle can be calculated using the SinC= 1/relative difference == C=sin-1(1/(3/100))
C=sin-1(100/3)
a step index fiber with large core diameter compared with the wavelength of the transmitted light...
A step index fibre has a numerical aperture of 0.16, a core refractive index of 1.45 and a core diameter of 90 mm. Calculate: 1. The refractive index of the cladding. 2. The acceptance angle θm and the confinement angle θ 0 m. 3. The approximate number of modes with a wavelength λ = 0.9 µm that the fibre can carry.
please solve the electro-optics problem Refractive indices for a step-index fiber are 1.52 for the core and 1.41 for the cladding. Determine: a) b) the critical angle; the numerical aperture; the maximum incidence angle om for light that is totally internally reflected.
The relative refractive index difference between the core axis and the cladding ofa graded index fiber is 0.7% when the refractive index at the core axis is 1.45.Estimate values for the numerical aperture of the fiber when:(a) the index profile is not taken into account; and(b) the index profile is assumed to be triangular.Comment on the results.
In the optical fiber below, the core has a refractive index equal to 1.5 and a cladding of refractive index of 1.4. a) What is the speed of light inside the core? b) What is the critical angle at the core-cladding interface? c) What is the maximum angle "t" that the rays leaving the source of light should make with the axis of the fiber so that total internal reflections takes place at the core-cladding interface?
a step index fiber has a solid acceptance angle in air of 0.115 radians relative refractive index difference of 0.9% estimate the speed of light fiber core
A step-index fiber has a solid acceptance angle in air of 0.115 radians and a relative refractive index difference of 0.9%. Estimate the speed of light in the fiber's core. (20 marks)
EXERCISE 1.3-2 Numerical Aperture of the Graded-Index Fiber. Consider a graded-index fiber with the index profile in (1.3-12) and radius a. A tay is incident fro a nto te fibe a its center, making an angle with the fiber axis (see Fig. 1.3-8). Show, in the paraxial Figure 1.3-8 Acceptance angle of a graded-index optical fiber approximation, that the numerical aperture is Numerical Aperture (Graded-Index Fiber) where ea is the maximum angle for which the ray trajectory is confined within...
Consider a 15 km long step-index fiber with n1= 1.53 and n2 = 1.50. What is the attenuation per kilometer in this fiber if an input power of 0.500 W results in the output power of 0.100 W ? Calculate the critical angle at the core-cladding interface and the NA (numerical aperture) for the fiber.
1.The core of an optical fiber is made out of a transparent material with a refractive index of 1.50 and the cladding is made out material with a refractive index of 1.44. As shown in the figure, a monochromatic light ray travels in air incident on the one side of the optical fiber and refracted. After that, the refracted ray will enter the core-cladding interface with its corresponding critical angle C. a) Calculate the value of 0? b) Find the...
The core of an optical fiber has an index of refraction of 1.29, while the index of refraction of the cladding surrounding the core is 1.17. What is the critical angle for total internal reflection at the core-cladding interface? critical angle: