EXERCISE 1.3-2 Numerical Aperture of the Graded-Index Fiber. Consider a graded-index fiber with the index profile...
The relative refractive index difference between the core axis and the cladding ofa graded index fiber is 0.7% when the refractive index at the core axis is 1.45.Estimate values for the numerical aperture of the fiber when:(a) the index profile is not taken into account; and(b) the index profile is assumed to be triangular.Comment on the results.
6. An optical fiber has an acceptance angle of 10.95 degrees. What's the numerical aperture for this fiber? A. 0.16 B. 1.02 C. 0.27 D. 0.19 7. An optical fiber has a core refractive index of 1.495 and a cladding refractive index of 1.47. What's the acceptance angle for this fiber? A. 13.11° B. 0.272° C. 9.79° D. 15.80° 8. While traveling through a cable, a signal loses 18.7 percent of its original power. What's this loss expressed in dB?...
1. (a) A laser beam enters an optical fiber with an incident angle of 6max as shown in Figure 1. Its corresponding refracted light is subsequently incident on the boundary between the core and the cladding whose refractive indices are ni and n2, respectively. The second incident angle satisfies the critical angle, 0c, for total internal reflection. Derive the Numerical Aperture (NA) of the fiber that dictates the maximum acceptance angle, amax. (6 Marks) ec Core ni 0max Cladding n2...
a step index fiber with large core diameter compared with the wavelength of the transmitted light has an acceptance angle in air of 22 and a relative refractive index difference of 3%.Estimate the numerical aperture and the critical angle at the core-cladding interface for the fiber
A step index fibre has a numerical aperture of 0.16, a core refractive index of 1.45 and a core diameter of 90 mm. Calculate: 1. The refractive index of the cladding. 2. The acceptance angle θm and the confinement angle θ 0 m. 3. The approximate number of modes with a wavelength λ = 0.9 µm that the fibre can carry.
please solve the electro-optics problem Refractive indices for a step-index fiber are 1.52 for the core and 1.41 for the cladding. Determine: a) b) the critical angle; the numerical aperture; the maximum incidence angle om for light that is totally internally reflected.
need Answers for c & d only. Everthing else is good. need answers for d & e only. Not c. Thank you 11:14 AM Wed Jun 19 71% Problem1: Fiber Optics different optical loss (attenuation) sources a) Provide six extrinsic sources) of an optical fiber system. b) Sketch and briefly explain the Total Internal Reflection (TIR) phenomenon. c) What is the difference between a step index fiber and a graded index fiber? (Hint: Consider the ray tracing of different modes...
3- Consider a bare fiber consisting of core of refractive index 1.48 and having air as cladding What is its NA? What is the maximum incident angle up to which light can be guided by the fiber? 4- Consider a fiber from which cladding is removed over a short length as shown below. Assume that the core and cladding refractive indices are 1.5 and 1.4 respectively, What ill happen to the output power if the bare portion of the fiber...
Consider a 15 km long step-index fiber with n1= 1.53 and n2 = 1.50. What is the attenuation per kilometer in this fiber if an input power of 0.500 W results in the output power of 0.100 W ? Calculate the critical angle at the core-cladding interface and the NA (numerical aperture) for the fiber.
Graded-index plastic optical fibre (GI POF) is expected to be used for high- speed local area networks (LANS) because of its large core which allows for low cost and easy installation. A particular GI POF has a core diameter of 200um, a maximum core index of 1.500 and a numerical aperture of 0.30. 2.c.i 2.c.ii What is the maximum acceptance angle for this fibre? [2 marks] What is the refractive index of the cladding material for this fibre? 12 marks/...