For optical fiber, the refractive index of the cladding compared to that of the core
Select one
a. is always smaller
b. is always larger
c. can be either bigger or smaller depending on specification
In optical fiber Electromagnetic wave is transported by using Total Internal Reflection.
Electromagnetic wave is trapped inside core for that Refractive index of core must be greater than that of cladding,If not then the electromagnetic waves will be leaked.
Therfore for the Total internal reflection and for no loss of energy the refractive index of cladding is always smaller
For optical fiber, the refractive index of the cladding compared to that of the core
Optical fiber has a core with refractive index 1.5, a cladding with refractive index 1.46 and a buffer coating with refractive index 1.4. What is the angle of total internal reflection in this fiber, if light is propagating in the core?
In the optical fiber below, the core has a refractive index equal to 1.5 and a cladding of refractive index of 1.4. a) What is the speed of light inside the core? b) What is the critical angle at the core-cladding interface? c) What is the maximum angle "t" that the rays leaving the source of light should make with the axis of the fiber so that total internal reflections takes place at the core-cladding interface?
1. An optical fiber has a core diameter of 4 micro-meters and the cladding refractive index n-= 1.46. In order to have a single mode propagation wavelengths at 850nm and above what is the maximum core refractive index we should use?
1.The core of an optical fiber is made out of a transparent material with a refractive index of 1.50 and the cladding is made out material with a refractive index of 1.44. As shown in the figure, a monochromatic light ray travels in air incident on the one side of the optical fiber and refracted. After that, the refracted ray will enter the core-cladding interface with its corresponding critical angle C. a) Calculate the value of 0? b) Find the...
The relative refractive index difference between the core axis and the cladding ofa graded index fiber is 0.7% when the refractive index at the core axis is 1.45.Estimate values for the numerical aperture of the fiber when:(a) the index profile is not taken into account; and(b) the index profile is assumed to be triangular.Comment on the results.
a step index fiber with large core diameter compared with the wavelength of the transmitted light has an acceptance angle in air of 22 and a relative refractive index difference of 3%.Estimate the numerical aperture and the critical angle at the core-cladding interface for the fiber
The core of an optical fiber has an index of refraction of 1.29, while the index of refraction of the cladding surrounding the core is 1.17. What is the critical angle for total internal reflection at the core-cladding interface? critical angle:
34C2 Optical fiber Eq. (34.9), (34.3) Cladding 112 Te 0; e Fiber core Telecom transmit signals with optical fiber. When a laser beam is within the Acceptance Angle Oa, it can keep going inside the fiber by total internal reflection. The refractive indices are ni 1.41, n2 = 1.40. Find a) 0:0, b) 0 ().
The core of an optical fiber has an index of refraction of 1.27 , while the index of refraction of the cladding surrounding the core is 1.15. What is the critical angle for total internal reflection at the core‑cladding interface?
3- Consider a bare fiber consisting of core of refractive index 1.48 and having air as cladding What is its NA? What is the maximum incident angle up to which light can be guided by the fiber? 4- Consider a fiber from which cladding is removed over a short length as shown below. Assume that the core and cladding refractive indices are 1.5 and 1.4 respectively, What ill happen to the output power if the bare portion of the fiber...