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What is the critical angle for light incident on water water = 1.33 from air nair = 1.00 for total internal reflection? Answe
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Answer #1

Solution:For total internal reflection to occur the light must to go from a denser medium ( i.e water ) to a rarer medium ( i.e. air)

so critical angle for light incident from water to air is

\theta _{c}=sin^-^1[{\frac{n_{air}}{n_{water}}}] =sin^-^1(1/1.33) = 48.75^o

Answer: 48.75o

note: we get critical angle only when light incident on air from water. but here in the quest it is given that light incidents on water from air . In this case we can't define critical angle.

Thank You.

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