Question

1.52E19 photons/s 4.27E19 photons/s Question 11 5 pts A square planar loop of coiled wire has a length of 0.25 m on a side and is rotated 60 times per second between the poles of a permanent magnet. The magnetic field between the poles is 0.75 T. If a peak voltage of 1 kV is generated in the coil, how many turns does it have? 56 turns 25 turns 60 turns O 120 turns 1000 turns Question 12 5 pts The figure shows a stationary conducting loop adjacent to a vertical current carrying wire. For which of the following conditions will a counter-clockwise induced current circulate in the stationary loop? Stan MacBook Air go COD 000 74 II FS F6 F7 FO

Answer 1

Given data: frequency, f = 10 radius, r = 1x10 m Mangnetic field, B= 2.5T = 750 m V Expression for peak voltage: me = NBAQ = NB (72) (271) Rearrange the equation N= 27 Bra / 1x103 V 27 (0.75T)(0.25 m)" (60) 56 turns (12) In order to produce counter clockwise induced current in loop. the current in the wire downwards and it value increasing. In the given sequence, third option is correct. Reason: If current flows doward, the magnetic flux is out of the page on the right side of the wire. and increasing due to the fact that the loop is being pulled away. According to Lenz's Law, the induced B field will oppose this increase. Thus, the new field points out of the page, which requires an induced counter clockwise current to produce such a magnetic field