Question

Need help to write the Explain the output results and null hypothesis between two variables below.

T-Test Group Statistics Std. Error Mean Mean Std. Deviation SEX. Respondent's sex Male N 1337 2.74 1.277 .035 Q1. Overall, how would you rate the quality of life for you and your family today? Would you say it is excellent, very good, good, fair or poor? Female 1677 2.72 1.179 .029 Independent Samples Test Levene's Test for Equality of Variances t-test for Equality of Means Std. Error Difference 95% Confidence Interval of the Difference Lower Upper F t df Mean Difference .025 Sig. .016 Sig. (2-tailed) .577 5.771 .559 3012 .045 -.063 .113 Q1. Overall, how would Equal variances you rate the quality of life assumed for you and your family today? Would you say it is Equal variances not excellent, very good, assumed good, fair or poor? .554 2754.529 .580 .025 .045 -.064 .114

Below are the two variables that I use for the Output above.

Q1      Overall, how would you rate the quality of life for you and your family today? Would you say it is... excellent, very good, good, fair or poor?

1        Excellent

2        Very good

3        Good

4        Fair

5        Poor

8        (DO NOT READ) Don’t know

9        (DO NOT READ) Refused

SEX     RECORD RESPONDENT SEX (DO NOT ASK)

1        Male

2        Female

Answer 1

The null and alternative hypotheses are: (in symbol) Ho: M1 = U2 H: U1 + U2 The null and alternative hypotheses are: (in words) Ho: There is no significant difference between mean rating of quality of life between male and female. H]: There is significant difference between mean rating of quality of life between male and female. The value of test statistic is: t=0.554 P-value = 0.580 Conclusion: The p-value of t test is greater than 0.05. Hence we fail to reject null hypothesis at 5% level of significance and conclude that there is no significant difference between mean rating of quality of life between male and female.