Question

• Purpose To learn how to read the output of the 2-independent-sample t-test and apply the results to a scenario Scenano. You are working at a summer camp near Grassy Key, FL, for autistic children Their parents have given permission for you to observe the children and rate their responsiveness in various stimulating situations. You would like to find out whether interaction with dolphins would affect the children's responsiveness. You randomly assign half the children to a group that will swim in a quiet cove with the camp counselors. The other half of the children will swim in a similar cove with the camp counselors and three dolphins, which are used to swimming with children 1) Group 1 Mean Group 2 Mean df Tabs Retain or Reject H. 2) Is this observational research or a true experiment? What is the clue in the scenario? 3) Write H, and H 4) Which kind of swimming treatment appeared to lead to higher responsiveness scores? 5) A) Use the critical-value decision rule tell whether you reject or retain H, and why B) Use the p-value decision rule tell whether your reject or retain H, and why. (Note that you should make exactly the same decision in both d and B, but from different perspectives). 6) is the difference in the average responsiveness scores significant? Explain and support your position with the correct - Test reporting convention

Please help!! I'm so lost!

Answer 1

1. Group 1 Mean = 25.93

Group 2 Mean = 29.8

df = 28

t = -1.535

Do not reject Ho

2. This is experiment because "randomly assing half the children to a group'.

3. The hypothesis being tested is:

H₀: µ₁ = µ₂

H₁: µ₁ ≠ µ₂

4. Swimming treatment 2 group students since they have a higher mean.

5. The critical value is 2.05.

Since 1.535 < 2.05, we do not reject the null hypothesis.

Since the p-value (0.138) is greater than the significance level (0.05), we fail to reject the null hypothesis.

6. Therefore, we can conclude that swimming with dolphins helped the children.