1. Group 1 Mean = 23.6
Group 2 Mean = 19
t = 6.2
Reject Ho
2. This is because each subject is tested twice.
3. The hypothesis being tested is:
H0: µd = 0
Ha: µd ≠ 0
4. The critical value is 2.145.
Since 6.2 > 2.145, we can reject the null hypothesis.
5. Since the p-value (0.000) is less than the significance level (0.05), we can reject the null hypothesis.
6. Therefore, we can conclude that swimming with dolphins helped the children.
Homework Assignment 4 SPSS Output - Saved View Table yout Review U ab A A Heading...
Please help!! I'm so lost! • Purpose To learn how to read the output of the 2-independent-sample t-test and apply the results to a scenario Scenano. You are working at a summer camp near Grassy Key, FL, for autistic children Their parents have given permission for you to observe the children and rate their responsiveness in various stimulating situations. You would like to find out whether interaction with dolphins would affect the children's responsiveness. You randomly assign half the children...
Question 5 4 pt The following is part of the output for a correlated groups t-test run in SPSS, based on the SPSS output is the test statistically significant (that is should you reject the null hypothesis)? Why or why not? Use information from the output to support your answer. Paired Samples Test 95% Confidence Interval of the Difference Std. Error Std. Deviation Mean Sig. (2 tailed) Mean Lower Upper Pair pretest- post-test -1.75000 3.19446 92216 -3.77966 -27966 -1.898 .044...
SPSS Lab Assignment #2 Output Analysis One Descriptives Depression_13 2323 WHITE BLACK AMER IND ASIAN HISPAN Mean 10.0010 10.0930 10.1038 10.1060 10.1062 10.0343 Std. Deviation 24975 27993 25361 27124 27267 26409 95% Confidence interval for Mean Std. ErrorLower Bound Upper Bound 00518 9.9908 10.0111 .00817 10.0770 10.1090 .03699 10.0294 10.1783 04952 10.0047 10.2073 .04158 10.0223 10.1901 00439 10.0257 10.0429 30 43 3617 Total ANOVA Depression 73 Mean Square Sum of Squares 7.230 244.967 1.808 26.651 Between Groups Within Groups Total...
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photos for each question are all in a row (1 point) In the following questions, use the normal distribution to find a confidence interval for a difference in proportions pu - P2 given the relevant sample results. Give the best point estimate for p. - P2, the margin of error, and the confidence interval. Assume the results come from random samples. Give your answers to 4 decimal places. 300. Use 1. A 80% interval for pı - P2 given that...