Question

Two converging lenses (f = 100mm) are placed 475mm apart. An object is placed 150mm to the left of the left-most lens. What is the magnification of object due to the two lenses? Answer:

Answer 1

ایسا 475mm I u + V too 100 300 300 fizfz= 100 mm > focal length of lenses u, es object distance for 1st lens. u=-1 sommf with segn. If u is image distance from ist lens then, - stato + -2 +3 → TV, = 300 mms right of leng1 because V is positive. i magnificatoon by lensl es mi = uu lm, Image formed by lens will be have as object for lens 2. U2=-475mm-300mm) > mi- Boomm -150 mm

U₂= is image -100+175 = its + Too 75 175X1000 - D 175X100 V2 175mm/ object distance for lens 2. If V2 distance (final image) from lens2 then, v tuz 2 + 2 = 1 + ta mm >= 17.00) mm Magráfication by lens 2 is me = 700 3x (175) :. Net magnification is m = mix m2 m=(-2)x( > m2 2667 175X100 75 Vz La » M2= M 4 3 (-4) >m= 8 3