Question

Let's say that the probability that an adult watches the news at least once per week is 0.60. We randomly survey 14 people. of interest is the number of people who watch the news at least once per week. Find the probability that at least six adults watch the news at least once per week. Select one: a. 6 14 b. 0.9417 c. 0.6429 d. 0.8499

Answer 1

The population proportion of success is p=0.60, also, 1-p=1- 0.60 = 0.4, and the sample size is n=14. We need to compute Pr(X26) Therefore, we get that Pr(826) = P+(8 = ) = Ź (7) » (1 – pya-i This implies that Pr(X > 6) = Pr(X = 6) + Pr(X = 7) + Pr( X = 8) + Pr(X = 9) + Pr(X = 10) + Pr( X = 11) +Pr( X = 12) + Pr( X = 0.414-6 (14) 0.607 x 0.414-7+ +(6) 0.608 x 0.414-8+ (64) 0.60° x 0.448 + (10) (10) 0.6010 0.414–10 = 0.0918 +0.1574 +0.2066 +0.2066 +0.1549 +0.0845 +0.0317 +0.0073 +0.0008 = 0.9417 (65) 0.60 0.606 x which means that the probability we are looking for is Pr(X > 6) = 0.9417

Option b is correct.

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