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The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 26 cm. find the dimensions of th
Atoy rocket is launched from a platform 42 meters above the ground in such a way that its height, h (in meters) after t secon
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As per HOMEWORKLIB POLICY, we are mandated to solve only one question. Here is the solution to your first question.

Solution Let width т length 2y – 3 s, Area length x Widen 26 - (2) - 3) + — 292 3% =) 26 - 26 с. 2у2 - Зу Il — 20 Б -) 2у2 -1length 29 - १ 9 - 2x 13 2 13 - 9 C ५ Cm length (। 13 width ]] Cm 2Please give it a thumbs up if you like the answer. Comment if any problem in solution. :)

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