Question

The length of a rectangle is 3 yd more than twice the width x. The area is 495 yd. Find the perimeter P of the rectangle. P-4
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Answer #1

width = x ya Length = 2x+3 yd Area Length x Width Area = 495 . 495 2 X (2x +3 ) 0 : 2X2 +3X - 495 2x2 of 33x - 300 - 495 oo XPerimeter 220 ltb) = 2( 33+15) 2 2 x 48 a 96 yards

Answer:

Perimeter = 96 yards

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