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You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width...

You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.

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P2(wtL)z44 Civen 44 2twtin) 22wt12) 44 w 20 L wt12 L lpSt し- 14 5Pcet

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