Question

The following intial rate data were obtained by adding 2.5 μg of a purified enzyme having molecular weight of 42,300 Daltons into 100 mL of water with the indicated concentrations of substrate C) So (mmol/L) 1.00 2.00 4.00 8.00 (HmoVLs) 4.50 7.90 11.10 15.20 Calculate the value of kCAT. KM and the pseudo first order rate constant.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Michaelis-menten equation:

Vo=Vmax [S]/Km+[S] where [S] =substrate concentration,Vmax=maximum velocity of enzyme-substrate reaction

Km=michaelis-menten constant,vo=reaction velocity

this can be rearranged to give : (1/Vo)=(Km/Vmax)*1/[S] +1/Vmax

A plot between 1/[S] vs 1/Vo is called lineweaver-Burk plot is linear with slope=Km/Vmax and y-intercept=1/Vmax

Also,Vmax=kcat*[E]

Vo=kcat*[E] [S]/Km+[S]

For high [S], km<<<[S]

So,Vo=kcat*[E] [S]/[S] =kcat [E]

thus kcat =pseudo first order rate constant as substrate is in large excess.

Data:

1/[So] (L/mmol)                       1/v(Ls/umol)

1.00                                            0.222

0.5                                               0.126

0.25                                             0.09

0.125                                           0.066

slope=km/Vmax=0.177 (Ls/umol) *(mmol/L)=0.177 *1000 (s)

intercept=1/Vmax=0.043 Ls/umol

Vmax=1/0.043=23.256 umol/Ls

km=0.177*1000 s *23.256 *10^-6 mol/Ls=4.116 *10^-3 mol/L=4.116 mmol/L

Also [E]=mol/volume

mol of enzyme=2.5ug/ 42300 g/mol=0.0000543 umol [1dalton=1g/mol]

[E]=0.0000543 umol/0.1L=0.000543 umol/L

So kcat=Vmax/[E]=(23.256 umol/Ls)/(0.000543 umol/L)=42828.729 s^-1

kcat=42828.729 s^-1

Spreadsheets Sign in Homeet Pae Layout Formulas Data Review View Special Features Cut Paste, 自Copy Format B 1 u B-隱 스·4 Merge

Add a comment
Know the answer?
Add Answer to:
The following intial rate data were obtained by adding 2.5 μg of a purified enzyme having...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please show work! 18.0 6.18 The following data were obtained on the initial rate of isomerization...

    Please show work! 18.0 6.18 The following data were obtained on the initial rate of isomerization of a compound S catalyzed by an enzyme E: [S]./(mmol dm-) 1.00 2.00 3.00 4.00 vo/(mmol dm-'s-1) (a) 4.5 9.0 15.0 (b) 14.8 25.0 45.0 59.7 (c) 58.9 120.0 180.0 238.0 The enzyme concentrations are (a) 1.00 mmol dm-?, (b) 3.00 mol dm-3, and (c) 10.0 mmol dm-?. Find the orders of reactions with respect to S and E, and the rate constant. Hints...

  • Please show your work, Thanks! 6.18 The following data were obtained on the initial rate of isomerization of a c...

    Please show your work, Thanks! 6.18 The following data were obtained on the initial rate of isomerization of a compound S catalyzed by an enzyme E: S]./(mmol dm") Va/(mmol dms) 2.00 3.00 1.00 4.00 15.0 9.0 4.5 (a) (b) 18.0 45.0 25.0 14.8 59.7 180.0 120.0 238.0 (c) 58.9 The enzyme concentrations are (a) 1.00 mmol dm, (b) 3.00 mol dm, and (c) 10.0 mmol dm Find the orders of reactions with respect to S and E, and the rate...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT