Question

PLEASE ANSWER PART A AND B

A Review Constants Periodic Table An expandable cube, initially 19 cm on each side contains 2.3 g of helium at 20°C. 1100 J of heat energy are transferred to this gas. What is the final pressure if the process is at constant volume? Express your answer in atmospheres. ΙπΙ ΑΣΦ ? p = atm Submit Request Answer Part B What is the final volume if the process is at constant pressure? Express your answer in cubic centimeters.

Answer 1

Sol:- m = -0.0 initial pres given side lengthech (A)=0-19m 0.0023 kg T= 20°C = 293 K A Q 1100 J pressure P = NRT; Vi where volume V; -0.1980.19x0.19 Vi = 6.86x10²m3 = 2.31 .Pis E 0.575X8.31X293 n = m -0.575 mol 6.86 X10-3 - Now Pi ~204086 Pa Q = nC,AT Q > AT = ncv where Cv=12.5 J/mol.k) Itoo ДТ 0.575X12.5 AT = 153.04 K final temperature Tf = T; +AT 3 Tf = 293 +153.04 T = 446.04 K ܒܝܐܘܢܬ 9 Pi Vi Pq Vs MRTL) (volume HRT: constant) Pq = Pi It = 204,086x446.04 293 Pq = 310,684.36 Pa

B) Now for constant pressure Q = nepat (: Cp220,8 g/mall ATE nep 1100 0.575X2018 2 91.97 K ATV 92k :- Final temperature + - Tit AT: 243+42 Tf = 385k fer constant prefsse Pf cP; Pf Vf ARTE Pivi HR Ti Ti Vi Ve & - 385 x6.86X163 293 = 0.009014 or) VA 0.01 m3 Answuessin A) pf = 310,684.36 Pa 3.066 atm Pf B) Vf = 0.00901 m3 ~0.01 m3 Hope will will get VOTE