A Review | Constants During the time 0.325 mol of an ideal gas undergoes an isothermal...

Question

Question

Answer 1

Answer #1

work done in a isothermal process = nRT ln(P1/P2)

where n = number of moles , R = universal gas constant

T = temperature in kelvin

P1 and P2 are initial and final pressure respectively

352 = 0.325*8.314*(273+22)*ln(P1/1.76)

P1 = 2.74 atm

so the initial pressure was 2.74 atm

Answer 2

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