Homework Answers
Correct option is"
(since repeated measure on latter factor means, same sample were used on factor 2)
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You read a report that states, "We used a 4 x 2 mixed factorial ANOVA with...
If you conducted the same experiment as above but used the same thirty people standing six...
If you conducted the same experiment as above but used the same thirty people standing six feet apart then four feet apart then ten feet apart and measured the amount of eye contact for each person, what test would you use now to determine if there is any difference in the average amount of eye contact at these three distances? Chi square goodness of fit Chi square test of independence Independent sample(simple) ANOVA Repeated measures(matched sample) ANOVA Factorial ANOVA
Answer True or False to the following: - If we were comparing the time it takes...
Answer True or False to the following: - If we were comparing the time it takes for a headache to subside to a certain level for six different dosages of the same medication using a one-way ANOVA procedure, then this problem has six levels and one factor. - In a one-way ANOVA, the entity on which a response variable is measured is called the level unit. - One assumption for the one-way ANOVA procedure is that the samples are independent...
Calculation Practice Compute the answers to Questions 4 - 6 without the use of statistical software....
Calculation Practice Compute the answers to Questions 4 - 6 without the use of statistical software. Be sure to supply all the intermediate information asked for by the question. To aid you, SS has been supplied. All three calculation practice questions will make use of the following dataset: Participant Factor A Lvll Factor A Lvl 2 Factor A Lvl 3 Factor B Lvl 1 Factor B Lvl 2 14 5. For this problem continue to ignore the levels of Factor....
1. Suppose you were researching the effects of psychological skills training (PST), such as goal setting and imagery, on golf-putting performance (scored out of 10). Twenty-eight participants (14 male...
1. Suppose you were researching the effects of psychological skills training (PST), such as goal setting and imagery, on golf-putting performance (scored out of 10). Twenty-eight participants (14 male and 14 female) were recruited for the study. Seven male and seven female participants were randomly allocated to each of the two conditions. How would you describe this research design? a. Two-way independent ANOVA b. One-way repeated-measures ANOVA c. Three-way mixed model ANOVA d. None of the above are appropriate 2....
For the following questions , identify the type of test that should be used. Simply use...
For the following questions , identify the type of test that should be used. Simply use the corresponding letter: A) One-sample z test (for a mean); B) One-sample t-test; C) One-sample z-test for a proportion (or a chi-squared goodness-of-fit); D) Chi-square goodness of fit (and a z-test is not appropriate); E) Two-sample z-test for a difference between proportions (or a chi-squared test for independence); F) Chi-square test for independence (and a z-test is not appropriate); G) Simple regression; H) Multiple...
pdf X - + Fit to page I Page view A' Read aloud Add notes 2...
pdf X - + Fit to page I Page view A' Read aloud Add notes 2 Problem IV. (12 points) For a random sample of 50 measurements of Xi, sample mean 11 = 200, sample standard deviations = 10. For X3, from a random sample of 50, sample mean 13 = 190 and sample standard deviation sa = 15. Assume that population distributions are approximately independent normal with unequal variances. Answer the following questions 1 through 3. 1. (5 points)...
For the following questions, identify the type of test that should be used. Simply use the...
For the following questions, identify the type of test that should be used. Simply use the corresponding letter: A) One-sample z test (for a mean); B) One-sample t-test; C) One-sample z-test for a proportion (or a chi-squared goodness-of-fit); D) Chi-square goodness of fit (and a z-test is not appropriate); E) Two-sample z-test for a difference between proportions (or a chi-squared test for independence); F) Chi-square test for independence (and a z-test is not appropriate); G) Simple regression; H) Multiple regression;...
1 A researcher wants to find out which type of classroom instruction significantly improves students’ test...
1 A researcher wants to find out which type of classroom instruction significantly improves students’ test performance. He designed four types of instruction for four samples of students. Later all four samples were given the same test and their average performance was compared. What statistical test should be used by the researcher to analyze the results of this study? A. Pearson correlation B. t-test for independent groups C. one-factor Anova for between groups D. Chi2 for Independence 2 A researcher...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatm...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...
Calculation Practice Compute the answers to Questions 4 - 6 without the use of statistical software. Be sure to supply all the intermediate information asked for by the question. To aid you, SS has been supplied. All three calculation practice questions will make use of the following dataset: Participant Factor A Lvll Factor A Lvl 2 Factor A Lvl 3 Factor B Lvl 1 Factor B Lvl 2 14 5. For this problem continue to ignore the levels of Factor....
pdf X - + Fit to page I Page view A' Read aloud Add notes 2 Problem IV. (12 points) For a random sample of 50 measurements of Xi, sample mean 11 = 200, sample standard deviations = 10. For X3, from a random sample of 50, sample mean 13 = 190 and sample standard deviation sa = 15. Assume that population distributions are approximately independent normal with unequal variances. Answer the following questions 1 through 3. 1. (5 points)...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...
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