The 1kg box shown in the figure has a force of f=21 N applied at an...
Homework Answers
When the block on an inclined plane than the normal reaction is
N = mgcos60
= 1*9.81*cos60
= 4.905 N
Calculate the magnitude of the friction force between the box and the surface .
Fr = µ*N
= 0.2* 4.905
= 0.981 N
Calculate the work done by the friction.
W = Fr*d
= 0.981 *20
= 19.62 J
Thus, the work done by the friction is 19.62 J .
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