Question

2. A 10 cm high object is located 30 cm from a -20 cm focal length diverging lens.

a) Find the image distance.

b) Find the magnification.

c) Find the image height.

d) Describe the image.

e) An astronaut on her way to Mars at 0.850c wishes to take a one-hour nap. How much time on earth passes during her nap?

Answer 1

2: 30 cm dom focal length 6 2-20 cm (u) = object his fance object height lho) By lens formula } ½ + the f Ý : . af ۔ -20 30 30-20 - -50 600 v 6oo v -12 n or some side v Image Zgonage zinfance 212 cm (in front of land) magnific ication (m) +12 = 0.4 is the magnificilio (m) 2014. + . 25 30 m Aldo m hi 004 ho hi to hi =4 cm hi 9004 Comage sgmage height - 4 cm @xas smage is -12 cm; hence image is virtual in nature! ocation is positive, so image is lens. virtual and erect and inforent of * And magnification is positive, eroet Tel.